添加直接解析Rule结构的接口

convenient/domain/query_rule/rule/query_rule_parser.go

@@ -22,6 +22,7 @@ func isSupportedLogicalOperator(logicalOperator string) bool {
 	return logicalOperator == LogicalOperatorAnd || logicalOperator == LogicalOperatorOr
 }
 
+// Rule 规则二叉树
 type Rule struct {
 	LogicalOperator string `json:"logicalOperator"`
 	Left            *Rule  `json:"left"`
@@ -142,6 +143,23 @@ func FormConditionClause(dbSchema string, scope string, domainName string, i *in
 	return c, nil
 }
 
+// FormConditionClauseByRules  使用Rule结构构造并返回条件语句
+// 参数:
+// - domainName: 领域名称
+// - rule: Rule的结构
+// - ruleParams: 规则参数
+// 返回值:
+// - 语句接口，当错误为nil时，语句接口也可能是nil，代表该规则并没有被赋值，所以是没有条件的
+// - 错误
+func FormConditionClauseByRules(domainName string, r Rule, ruleParams map[string]any) (clause.Clause, error) {
+	c, err := formConditionClause(domainName, r, ruleParams)
+	if err != nil {
+		return nil, err
+	}
+
+	return c, nil
+}
+
 func getEnabledRule(dbSchema string, scope string, domainName string, i *infrastructure.Infrastructure) (Rule, error) {
 	dbExecutor := i.DBExecutor()